Absorption with chernical reaction
(a) Rework the problem discussed in the text in S18.4, but take z = 0 to be the bottom of the beaker and z = L at the gas-liquid interface.
(b) In solving Eq. 18.4-7, we took the solution to be of the sum of two hyperbolic functions.
Try solving the problem by using the equally valid solution Г = C1 exp (bζ + C2 exp (– bζ)
(c) In what way do the results in Eqs. 18.4-10 and 12 simplify for very large L for very small L? Interpret the results physically.